barcode reader code in asp.net Figure B12 in Software

Generator QR in Software Figure B12

Figure B12
QR Code Reader In None
Using Barcode Control SDK for Software Control to generate, create, read, scan barcode image in Software applications.
QR Code JIS X 0510 Creation In None
Using Barcode creation for Software Control to generate, create QR-Code image in Software applications.
B19 The power factor is most nearly
QR Scanner In None
Using Barcode scanner for Software Control to read, scan read, scan image in Software applications.
Generating QR Code 2d Barcode In C#
Using Barcode generator for .NET framework Control to generate, create QR-Code image in VS .NET applications.
a 10 b 06 leading c 0866 leading d 0 e 08 lagging Solution: The impedance angle is: = tan 1 40 = 5313 30
QR Drawer In .NET
Using Barcode printer for ASP.NET Control to generate, create Quick Response Code image in ASP.NET applications.
Printing Quick Response Code In Visual Studio .NET
Using Barcode maker for .NET Control to generate, create Denso QR Bar Code image in VS .NET applications.
Therefore, the power factor is: pf = cos = 06, leading We can also get the answer directly from the expression for the current IAB The correct answer is b
QR-Code Maker In Visual Basic .NET
Using Barcode encoder for Visual Studio .NET Control to generate, create QR Code 2d barcode image in .NET applications.
ANSI/AIM Code 128 Generation In None
Using Barcode creation for Software Control to generate, create Code 128C image in Software applications.
B20 The total real power delivered from the source to the load is most nearly a 1496 W b 580 W c 1742 W d 2904 W e 850 W
Data Matrix ECC200 Generator In None
Using Barcode creation for Software Control to generate, create DataMatrix image in Software applications.
Barcode Printer In None
Using Barcode maker for Software Control to generate, create bar code image in Software applications.
Solution: The total power P delivered to the balanced load is: P = 3VAB IAB cos = 3 220 44 06 = 17424 1742 W The answer is c
Making UPC Code In None
Using Barcode printer for Software Control to generate, create UPC Code image in Software applications.
Bar Code Printer In None
Using Barcode generation for Software Control to generate, create barcode image in Software applications.
Diode Applications 8 covers all of the diode material that is relevant to the FE exam The following examples illustrate typical questions
RoyalMail4SCC Creation In None
Using Barcode printer for Software Control to generate, create Royal Mail Barcode image in Software applications.
EAN / UCC - 13 Reader In Java
Using Barcode scanner for Java Control to read, scan read, scan image in Java applications.
Appendix B
Draw Barcode In Java
Using Barcode maker for Eclipse BIRT Control to generate, create barcode image in Eclipse BIRT applications.
UPC-A Supplement 5 Generator In Objective-C
Using Barcode printer for iPhone Control to generate, create UPCA image in iPhone applications.
Fundamentals of Engineering (FE) Examination
Draw GS1 128 In None
Using Barcode generator for Font Control to generate, create EAN / UCC - 14 image in Font applications.
Read USS Code 39 In C#
Using Barcode recognizer for .NET Control to read, scan read, scan image in VS .NET applications.
Check Your Understanding
Code 3/9 Printer In None
Using Barcode maker for Online Control to generate, create Code-39 image in Online applications.
Barcode Maker In .NET Framework
Using Barcode generator for ASP.NET Control to generate, create barcode image in ASP.NET applications.
B21 The circuit of Figure B13 is a a Peak detector b Half-wave recti er d Voltage doubler e Full-wave recti er
Solution: The correct answer is e c Bridge recti er
L vin C vout C
B22 The inductor L and the capacitor C serve the function of
a b c d e Converting the AC input to DC output Increasing the peak value of the output voltage Protecting the diodes A high-pass lter Reducing the ripple component of the output voltage
Figure B13
Solution: The correct answer is e
B23 The ideal diode D in Figure B14 will always conduct if:
a V1 is greater than V2 c V1 is greater than 1 V e R1 is an open circuit b V2 is greater than V1 d R2 is an open circuit
R1 V1
i D V2 R2
Solution: Using the methodology developed in 8, we assume that D conducts, resulting in the following expression for the diode current i= V1 V2 R1
Figure B14
This expression will result in a positive current only if V1 is greater than V2 When this condition applies, the assumption that the diode conducts is correct; thus, a is the correct answer
Operational Ampli ers The coverage of operational ampli ers in this book is well beyond the scope of the FE Exam Sections 121 to 123 cover all of the required material on ideal op-amps
Check Your Understanding
B24 In the circuit of Figure B15, which value is closest to v3 if R1 = 22 k , R2 = 15 k , R3 = 18 k , v1 = 120 mV and v2 = 40 mV a 250 mV b 500 mV c 500 mV d 146 V e 146 V
Solution: Using the summing ampli er equation in 12, we calculate: v3 = 18 R3 R3 18 (120) ( 40) = 5018 mV v1 v2 = R1 R2 22 15
R3 R1 v1 v2 R2 v3 +
Figure B15
Thus, the nearest answer is c
B25 In Figure B15, if R1 = 22 k , R3 = 18k , v1 = 120 mV and v2 = 40 mV, choose the value of R2 such that v3 = 0 a 12 k b 5 k c 733 k d 0733 k e 05 k
Appendix B
Fundamentals of Engineering (FE) Examination
Solution: Using the summing ampli er equation in 12, we calculate: v3 = 18 R3 R3 18 (120) v1 v2 or 0 = ( 40) R1 R2 22 R2
40 120 = 22 R2 22 40 = 0733 k 120 Thus, the nearest answer is d R2 =
Electric and Magnetic Fields Some of the basic ideas on electric elds, voltage, charge, and work are covered in 2 Faraday s law and other magnetic eld concepts are covered in 16 Two examples are given below
Check Your Understanding
B26 Which of the following is a true characteristic of magnetic ux lines
a b c d e They cross each other They begin and end on electric charges They are parabolic They are continuous None of the above
Solution: As discussed in 15, magnetic ux lines are continuous Thus, d is the correct answer area = 5 in2 , and the mean ux path length = 2 in, the total reluctance R of the magnetic circuit in (A t in2 )/Wb is a 1 105 b 2 105 c 15 105 d 35 104 e 2 105 Solution: From 16, the relationship between magnetomotive force and ux is
Copyright © OnBarcode.com . All rights reserved.