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Generation QR Code in .NET ANSWERS TO SUPPLEMENTARY PROBLEMS

ANSWERS TO SUPPLEMENTARY PROBLEMS
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18.11 (a) t <
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1 1 1 h and t > 1 h; (b) < t < 1 h; (c) t = h and t = 1 h; (d) 0.75 mi/h. 2 2 2 18.13 320 ft/sec. 18.14 (a) t = 0 and t = 5; (b) t = 2.5; (c) no.
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18.12 13 units.
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18.15 (a) 5 sec; (b) 122.5 m. 18.16 (a) 196 ft; (b) 112 ft/sec.
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19.4 $30 per set. 19.5 $7 per unit. 19.6 24 ft2 /ft. G/ t = 54).
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19.7 40 km/sec (at t = 1000 sec). 19.9 (a) 9; (b) 6. 19.10 y = 2.
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19.8 (a) 18 gal/sec (ie., G = 18); (b) 54 gal/sec (i.e.,
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20.5 24/7 ft/min. 20.6 3.14/ 1 ft/min. 20.7 8 ft/sec. 20.8 64 ft/sec.
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20.9 12/ 3.82 mm/sec.
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20.10 4 1.27 in/sec.
20.11 400 1256 m2 /min. 20.13 36 units/sec. 20.16 r = 1/ . 20.19 4 2 5.64 mi/h.
20.12 (a) 10 mm; (b) increasing at 6/ 5 = 2.69 mm/sec. 20.14 Decreasing at 3 units/sec. 2 20.15 30 mm3 /sec. 20.18 500 km/h. 20.21 1,
20.17 Increasing at 6 units/sec. 20.20 16 225 3.14
0.071 m/min.
20.22 5 ft/sec.
20.23 6 ft/sec.
45 ft/sec. 8
20.25 0 mi/h.
20.26 12 units/sec.
21.6 (a) 53 373 12.35 159 65 50 7.1429; (b) 8.8333; (c) 4.9733; (d) 4.1167; (e) 0.4969; ( f ) 0.6771; 7 6 75 3 320 96 193 323 647 (g) 0.4021; (h) 8.9722; (i) 5.9907. 480 36 108 21.8 1920 78.3 gal. 77 21.9 (a) 5 15.7 cm3 ; (b) 5.1 16.0 cm3 . 21.13 max (1.8525, 1.8475) = 1.8525 ft2 .
21.7 0.994 cm3 .
21.10 9%.
1 mi 210 ft. 8
21.12 (a) 6; (b) 6.
21.15 (a) 1.189207115; (b) 1.587401052; (c) 1.872171231; (d) 1.817120593. 21.17 (a) 1.324717957; (b) 0.6823278038; (c) 1.306562965 and 0.5411961001; (d) 1.179509025; (e) 0.8793852416, 1.347296355, and 2.532088886; ( f ) 1.671699882; (g) 1.618033989, 0.6180339888, and 1. 21.18 1.867460025. 21.19 1.090942496.
ANSWERS TO SUPPLEMENTARY PROBLEMS
[ANS.
2 1 1 2 2 1 22.5 3 ; (b) 6 x; (c) (x + 5) 3/2 = ; (d) (x 1) 5/3 = ; (e) (2 x 2 )(x 2 + 1) 7/4 ; 4 9 4 x 4( x + 5)3 9( 3 x 1)5 ( f ) 4(x 3)(5x 2 6x 3); (g) 2x + 4 . (1 x)4
1 2x 2 1 . 22.6 (a) 3 ; (b) 3 ; (c) 5 ; (d) y y y (x + 2y)3 22.7 (a) and (b) y = 1 3/2 x ; (c) (a). 2 = 96x, y(4) = 96, y(n) = 0 for n > 4; = (2 3)x 4 , . . . , y(n) = ( 1)n n ! x (n+1) for n > 2. 3 15 7/2 x = x 5/2 , y(4) = ,..., 8 16
22.8 (a) y = 16x 3 4x, y = 48x 2 4, y (c) y =
(b) y = 4x + 1 x 2 , y = 4 + 2x 3 , y
1 1/2 1 x , y = x 3/2 , y 2 4 (n) = ( 1)n 1 (1)(3)(5) (2n 3) x (2n 1)/2 for n > 1. y 2n 2 , y = 4(x 1) 3 , y = 12(x 1) 4 , . . . , y(n) = ( 1)n 2(n !)(x 1) (n+1) ; (d) y = 2(x 1) (e) y = (3 + x) 2 , y = 2(3 + x) 3 , y ( f ) y = 2x 3 , y = 3 2x 4 , y 22.9 (a) a = 2 = 0; (b) 3; (c) 0. 2 22.10 y = . 3 22.11 dy d2y 1 = 0, 2 = . dx 2 dx 22.12 (a) K = 1 3 , L = ; (b) no. 7 7 = 6(3 + x) 4 , . . . , y(n) = ( 1)n n! (3 + x) (n+1) ; = 4 3 2x 5 , . . . , y(n) = ( 1)n (n + 1)! x (n+2) .
22.13 (a) h (x) = f (x)g (x) + 2f (x)g (x) + f (x)g(x), h (x) = f (x)g (x) + 3f (x)g (x) + 3f (x)g (x) + f (x)g(x), h(4) (x) = f (x)g(4) (x) + 4f (x)g (x) + 6f (x)g (x) + 4f (x)g (x) + f (4) (x)g(x); n! n (k) n f (x)g(n k) (x), where and f (0) (x) = f (x). For the meaning of the = k k!(n k)! k k=0 see Section 30.1. (b) h(n) (x) = 22.14 g(x)f (x) f (x)g (x) g (x) H (x). 2 g(x) (g(x))2
notation,
22.15 (a) 5.4 ft/sec2 ; (b) 270 ft at t =10 sec. 22.16 (a) At t = 0 and t = 5. (b) At t = 2.5. (c) When t = 0, f (t) = 6 and g (t) = 4, so that they are moving in opposite directions. When t = 5, f (t) = 4 and g (t) = 6; again, they are moving in opposite directions.
23.4 (a) Concave upward for all x. (b) Upward for x < 5 or x > 4, downward for 5 < x < 4; I( 5, 1371), I( 4, 1021). 1 1 (c) Upward for x > 5, downward for x < 5; I( 5, 221). (d) Upward for x > , downward for x < ; no in ection 2 2 points. (e) Upward for x < 3, downward for x > 3; I(3, 162). 23.5 (a) 1.5 (min); (b) 0 (max), 3 (min), 3 (min); (c) 4 (min), 23.6 See Fig. A-10. 23.7 (d). 23.8 B and E. 2 (max); (d) 0 (max), 2 (min); (e) 0 (min). 3
ANS.]
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