zen barcode ssrs The Thevenin equivalent circuit is shown in Fig. 4-29. current is I4 agreeing with Problem 4.12. in Software

Maker QR Code in Software The Thevenin equivalent circuit is shown in Fig. 4-29. current is I4 agreeing with Problem 4.12.

The Thevenin equivalent circuit is shown in Fig. 4-29. current is I4 agreeing with Problem 4.12.
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Vin =41 Vin A 150=41 RL 41RL 150
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Use superposition to nd the current I from each voltage source in the circuit shown in Fig. 4-30.
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Loop currents are chosen such that each source contains only one current.
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CHAP. 4]
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ANALYSIS METHODS
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Fig. 4-29
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Fig. 4-30  54 27 27 74  I1 I2   460 200 
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From the 460-V source, I10 I 0 and for the 200-V source I100 I 00 Then, 200 27 1:65 A 3267 460 74 10:42 A 3267
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I I 0 I 00 10:42 1:65 8:77 A
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Fig. 4-31(a)
Obtain the current in each resistor in Fig. 4-31(a), using network reduction methods.
As a rst step, two-resistor parallel combinations are converted to their equivalents. For the 6  and 3 , Req 6 3 = 6 3 2 . For the two 4- resistors, Req 2 . The circuit is redrawn with series resistors added [Fig. 4-31(b)]. Now the two 6- resistors in parallel have the equivalent Req 3 , and this is in series with the 2 . Hence, RT 5 , as shown in Fig. 4-31(c). The resulting total current is
ANALYSIS METHODS
[CHAP. 4
Fig. 4-31 (cont.) 25 5A 5
IT
Now the branch currents can be obtained by working back through the circuits of Fig. 4-31(b) and 4-31(a) IC IF 1 IT 2:5 A 2 ID IE 1 IC 1:25 A 2 3 5 I A 6 3 T 3 6 10 IB I A 6 3 T 3 IA
Find the value of the adjustable resistance R which results in maximum power transfer across the terminals ab of the circuit shown in Fig. 4-32.
Fig. 4-32 First a Thevenin equivalent is obtained, with V 0 60 V and R 0 11 . power transfer occurs for R R 0 11 , with Pmax V 02 81:82 W 4R 0 By Section 4.10, maximum
Supplementary Problems
4.17 Apply the mesh current method to the network of Fig. 4-33 and write the matrix equations by inspection. Obtain current I1 by expanding the numerator determinant about the column containing the voltage sources to show that each source supplies a current of 2.13 A.
CHAP. 4]
ANALYSIS METHODS
Fig. 4-33 4.18 Loop currents are shown in the network of Fig. 4-34. currents. Ans. 3.55 A, 1:98 A, 2:98 A Write the matrix equation and solve for the three
Fig. 4-34
The network of Problem 4.18 has been redrawn in Fig. 4-35 for solution by the node voltage method. tain node voltages V1 and V2 and verify the currents obtained in Problem 4.18. Ans. 7.11 V, 3:96 V
Fig. 4-35
In the network shown in Fig. 4-36 current I0 7:5 mA. voltage Vs . Ans. 0.705 V
Use mesh currents to nd the required source
Use appropriate determinants of Problem 4.20 to obtain the input resistance as seen by the source voltage Ans: 23:5  Vs . Check the result by network reduction.
ANALYSIS METHODS
[CHAP. 4
Fig. 4-36
For the network shown in Fig. 4-36, obtain the transfer resistance which relates the current I0 to the source voltage Vs . Ans: 94:0  For the network shown in Fig. 4-37, obtain the mesh currents. Ans. 5.0 A, 1.0 A, 0.5 A
Fig. 4-37 4.24 Using the matrices from Problem 4.23 calculate Rinput;1 , Rtransfer;12 , and Rtransfer;13 . Ans: 10 ; 50 ; 100  In the network shown in Fig. 4-38, obtain the four mesh currents. Ans. 2.11 A, 0:263 A, 2:34 A, 0.426 A
Fig. 4-38
For the circuit shown in Fig. 4-39, obtain Vo:c: , Is:c: , and R 0 at the terminals ab using mesh current or node voltage methods. Consider terminal a positive with respect to b. Ans: 6:29 V; 0:667 A; 9:44 
CHAP. 4]
ANALYSIS METHODS
Fig. 4-39 4.27 Use the node voltage method to obtain Vo:c: and Is:c: at the terminals ab of the network shown in Fig. 440. Consider a positive with respect to b. Ans: 11:2 V; 7:37 A
Fig. 4-40 4.28 Use network reduction to obtain the current in each of the resistors in the circuit shown in Fig. 4-41. Ans. In the 2.45- resistor, 3.10 A; 6.7 , 0.855 A; 10.0 , 0.466 A; 12.0 , 0.389 A; 17.47 , 0.595 A; 6.30 , 1.65 A
Fig. 4-41 4.29 Both ammeters in the circuit shown in Fig. 4-42 indicate 1.70 A. If the source supplies 300 W to the circuit, Ans: 23:9 ; 443:0  nd R1 and R2 .
Fig. 4-42
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