 Home
 Products
 Integration
 Tutorial
 Barcode FAQ
 Purchase
 Company
ssrs barcodelib Copyright 2003, 1997, 1986, 1965 by The McGrawHill Companies, Inc. Click Here for Terms of Use. in Software
Copyright 2003, 1997, 1986, 1965 by The McGrawHill Companies, Inc. Click Here for Terms of Use. QR Code 2d Barcode Recognizer In None Using Barcode Control SDK for Software Control to generate, create, read, scan barcode image in Software applications. QR Code 2d Barcode Creation In None Using Barcode generation for Software Control to generate, create QR image in Software applications. CIRCUIT CONCEPTS
Decoding QR Code In None Using Barcode recognizer for Software Control to read, scan read, scan image in Software applications. Draw Quick Response Code In C#.NET Using Barcode generator for .NET framework Control to generate, create QR Code JIS X 0510 image in Visual Studio .NET applications. [CHAP. 2
QR Code JIS X 0510 Generation In .NET Framework Using Barcode creation for ASP.NET Control to generate, create QRCode image in ASP.NET applications. Paint QRCode In VS .NET Using Barcode generator for Visual Studio .NET Control to generate, create QR Code JIS X 0510 image in VS .NET applications. Fig. 22 Encode QR Code ISO/IEC18004 In Visual Basic .NET Using Barcode generator for Visual Studio .NET Control to generate, create QR image in .NET framework applications. EAN / UCC  14 Drawer In None Using Barcode encoder for Software Control to generate, create EAN 128 image in Software applications. Fig. 23 Data Matrix 2d Barcode Maker In None Using Barcode drawer for Software Control to generate, create DataMatrix image in Software applications. Barcode Generator In None Using Barcode printer for Software Control to generate, create bar code image in Software applications. In general, a coil can be represented by either a series or a parallel arrangement of circuit elements. The frequency of the applied voltage may require that one or the other be used to represent the device. Barcode Drawer In None Using Barcode maker for Software Control to generate, create barcode image in Software applications. Painting UCC  12 In None Using Barcode maker for Software Control to generate, create GTIN  12 image in Software applications. SIGN CONVENTIONS
Paint International Standard Serial Number In None Using Barcode encoder for Software Control to generate, create International Standard Serial Number image in Software applications. EAN 13 Maker In C# Using Barcode maker for .NET framework Control to generate, create EAN13 Supplement 5 image in .NET framework applications. A voltage function and a polarity must be speci ed to completely describe a voltage source. The polarity marks, and , are placed near the conductors of the symbol that identi es the voltage source. If, for example, v 10:0 sin !t in Fig. 24(a), terminal A is positive with respect to B for 0 > !t > , and B is positive with respect to A for > !t > 2 for the rst cycle of the sine function. GS1128 Reader In C#.NET Using Barcode reader for .NET framework Control to read, scan read, scan image in VS .NET applications. USS Code 128 Maker In Java Using Barcode maker for Java Control to generate, create Code128 image in Java applications. Fig. 24 Generate Barcode In .NET Using Barcode maker for Visual Studio .NET Control to generate, create bar code image in .NET framework applications. Draw GS1  13 In Java Using Barcode generator for Java Control to generate, create EAN13 image in Java applications. Similarly, a current source requires that a direction be indicated, as well as the function, as shown in Fig. 24(b). For passive circuit elements R, L, and C, shown in Fig. 24(c), the terminal where the current enters is generally treated as positive with respect to the terminal where the current leaves. The sign on power is illustrated by the dc circuit of Fig. 25(a) with constant voltage sources VA 20:0 V and VB 5:0 V and a single 5 resistor. The resulting current of 3.0 A is in the clockwise direction. Considering now Fig. 25(b), power is absorbed by an element when the current enters the element at the positive terminal. Power, computed by VI or I 2 R, is therefore absorbed by both the resistor and the VB source, 45.0 W and 15 W respectively. Since the current enters VA at the negative terminal, this element is the power source for the circuit. P VI 60:0 W con rms that the power absorbed by the resistor and the source VB is provided by the source VA . GS1  13 Creator In VB.NET Using Barcode generator for .NET framework Control to generate, create EAN13 image in .NET framework applications. Painting Code 39 In Visual C# Using Barcode drawer for Visual Studio .NET Control to generate, create ANSI/AIM Code 39 image in VS .NET applications. CHAP. 2] CIRCUIT CONCEPTS
Fig. 25 VOLTAGECURRENT RELATIONS
The passive circuit elements resistance R, inductance L, and capacitance C are de ned by the manner in which the voltage and current are related for the individual element. For example, if the voltage v and current i for a single element are related by a constant, then the element is a resistance, R is the constant of proportionality, and v Ri. Similarly, if the voltage is the time derivative of the current, then the element is an inductance, L is the constant of proportionality, and v L di=dt. Finally, if the current in the element is the time derivative of the voltage, then the element is a capacitance, C is the constant of proportionality, and i C dv=dt. Table 21 summarizes these relationships for the three passive circuit elements. Note the current directions and the corresponding polarity of the voltages. Table 21 Circuit element Units Voltage Current Power
ohms () v Ri (Ohms s law) p vi i2 R
Resistance
henries (H) di dt
v dt k1 p vi Li
di dt
Inductance
farads (F) i dt k2 i C
dv dt
p vi Cv
dv dt
Capacitance
CIRCUIT CONCEPTS
[CHAP. 2
RESISTANCE
All electrical devices that consume energy must have a resistor (also called a resistance) in their circuit model. Inductors and capacitors may store energy but over time return that energy to the source or to another circuit element. Power in the resistor, given by p vi i2 R v2 =R, is always positive as illustrated in Example 2.1 below. Energy is then determined as the integral of the instantaneous power t2 t2 1 t2 2 2 w p dt R i dt v dt R t1 t1 t1 EXAMPLE 2.1. A 4.0 resistor has a current i 2:5 sin !t (A). Find the voltage, power, and energy over one cycle. ! 500 rad/s. v Ri 10:0 sin !t V p vi i2 R 25:0 sin2 !t W ! t t sin 2!t J w p dt 25:0 2 4! 0 The plots of i, p, and w shown in Fig. 26 illustrate that p is always positive and that the energy w, although a function of time, is always increasing. This is the energy absorbed by the resistor. Fig. 26 CHAP. 2]

