ssrs barcodelib I2 1:3 0:2167 S 6 V2 I1 0 in Software

Creator Code39 in Software I2 1:3 0:2167 S 6 V2 I1 0

I2 1:3 0:2167 S 6 V2 I1 0
Code 3 Of 9 Recognizer In None
Using Barcode Control SDK for Software Control to generate, create, read, scan barcode image in Software applications.
Paint Code 3 Of 9 In None
Using Barcode generator for Software Control to generate, create Code 39 Extended image in Software applications.
CHAP. 1]
Scanning Code 39 Extended In None
Using Barcode recognizer for Software Control to read, scan read, scan image in Software applications.
Code-39 Generator In C#.NET
Using Barcode generation for VS .NET Control to generate, create Code39 image in .NET framework applications.
CIRCUIT ANALYSIS: PORT POINT OF VIEW
Code 39 Full ASCII Generator In VS .NET
Using Barcode creator for ASP.NET Control to generate, create Code 39 Full ASCII image in ASP.NET applications.
Code39 Creation In VS .NET
Using Barcode printer for .NET Control to generate, create Code 39 Full ASCII image in .NET applications.
Use (1.8), (1.9), and (1.16) to (1.19) to nd the h parameters in terms of the z parameters.
Printing Code 3/9 In VB.NET
Using Barcode generation for Visual Studio .NET Control to generate, create Code 3 of 9 image in .NET applications.
DataMatrix Creation In None
Using Barcode creation for Software Control to generate, create Data Matrix ECC200 image in Software applications.
Setting V2 0 in (1.9) gives 0 z21 I1 z22 I2 from which we get h21 or I2 z21 I z22 1 1
EAN13 Generator In None
Using Barcode encoder for Software Control to generate, create European Article Number 13 image in Software applications.
Painting Bar Code In None
Using Barcode encoder for Software Control to generate, create bar code image in Software applications.
I2 z 21 I1 V2 0 z22
Generating Bar Code In None
Using Barcode creation for Software Control to generate, create bar code image in Software applications.
GS1 128 Generator In None
Using Barcode creator for Software Control to generate, create GS1 128 image in Software applications.
Back substitution of (1) into (1.8) and use of (1.16) give V z z z11 12 21 h11 1 I1 V2 0 z22 Now, with I1 0, (1.8) and (1.9) become V1 z12 I2 so that, from (1.17), h12 and, from (1.19), h22 and V2 z22 I2
Code 2 Of 7 Generator In None
Using Barcode drawer for Software Control to generate, create Code-27 image in Software applications.
Generating UPC Symbol In Objective-C
Using Barcode maker for iPad Control to generate, create UPCA image in iPad applications.
V1 z 12 V2 I1 0 z22
Code 128B Decoder In None
Using Barcode recognizer for Software Control to read, scan read, scan image in Software applications.
Painting Code-39 In Java
Using Barcode maker for Java Control to generate, create Code39 image in Java applications.
I2 I 1 2 V2 I1 0 z22 I2 z22
Generate Code 128 In Visual Basic .NET
Using Barcode drawer for .NET framework Control to generate, create Code 128C image in .NET applications.
EAN128 Scanner In VB.NET
Using Barcode decoder for Visual Studio .NET Control to read, scan read, scan image in .NET applications.
The h parameters of the two-port network of Fig. 1-20 are h11 100 ; h12 0:0025; h21 20, and h22 1 mS. Find the voltage-gain ratio V2 =V1 .
Print Barcode In .NET Framework
Using Barcode printer for ASP.NET Control to generate, create bar code image in ASP.NET applications.
UPC Code Maker In None
Using Barcode maker for Online Control to generate, create UPC-A Supplement 5 image in Online applications.
1 kW + Vs _ I1 + V1 _ I1 I2 Two-port network I2 + V2 _ RL = 2 kW
Fig. 1-20 By Ohm s law, I2 V2 =RL , so that (1.15) may be written V2 I2 h21 I1 h22 V2 RL
Solving for I1 and substitution into (1.14) give V1 h11 I1 h12 V2 which can be solved for the voltage gain ratio: V2 1 1 200 V1 h12 h11 =h21 1=RL h22 0:0025 100=20 1=2000 0:001 1=RL h22 V2 h22 h12 V2 h21
CIRCUIT ANALYSIS: PORT POINT OF VIEW
[CHAP. 1
Determine the Thevenin equivalent voltage and impedance looking right into port 1 of the circuit of Fig. 1-20.
The Thevenin voltage is V1 of (1.8) with port 1 open-circuited: VTh V1 jI1 0 z12 I2 Now, by Ohm s law, V2 RL I2 But, with I1 0, (1.9) reduces to V2 z22 I2 Subtracting (2) from (3) leads to z22 RL I2 0 Since, in general, z22 RL 6 0, we conclude from (4) that I2 0 and, from (1), VTh 0. Substituting (2) into (1.8) and (1.9) gives V1 z11 I1 z12 I2 z11 I1 z12 V RL 2 z22 V RL 2 5 4 3 2 1
V2 z21 I1 z22 I2 z21 I1
V1 is found by solving for V2 and substituting the result into (5): V1 z11 I1 z12 z21 I z22 RL 1
Then ZTh is calculated as the driving-point impedance V1 =I1 : ZTh Vdp V1 z z z11 12 21 Idp I1 z22 RL
Find the Thevenin equivalent voltage and impedance looking into port 1 of the circuit of Fig. 1-20 if RL is replaced with a current-controlled voltage source such that V2 I1 , where is a constant.
As in Problem 1.16, VTh V1 jI1 0 z22 I2 But if I1 0, (1.9) and the de ning relationship for the controlled source lead to V2 I1 0 z22 I2 from which I2 0 and, hence, VTh 0. Now we let V1 Vdp , so that I1 Idp , and we determine ZTh as the driving-point impedance. From (1.8), (1.9), and the de ning relationship for the controlled source, we have V1 Vdp z11 Idp z12 I2 V2 Idp z21 Idp z22 I2 Solving (2) for I2 and substituting the result into (1) yields Vdp z11 Idp z12 from which Thevenin impedance is found to be ZTh Vdp z11 z22 z12 z21 z22 Idp z21 Idp z22 1 2
CHAP. 1]
CIRCUIT ANALYSIS: PORT POINT OF VIEW
The periodic current waveform of Fig. 1-21 is composed of segments of a sinusoid. Find (a) the average value of the current and (b) the rms (e ective) value of the current.
i, A Im
Fig. 1-21 (a) Because i t 0 for 0 !t < , the average value of the current is, according to (1.20), 1  I Im 1 cos I0 I sin !t d !t m cos !t  !t  m  
(b) By (1.21) and the identity sin2 x 1 1 cos 2x , 2 1  2 I2  Im sin2 !t d !t m 1 cos 2!t d !t I2  2   2  2  I 1 I 1 m !t sin 2!t m  sin 2 2 2 2 2 !t s  1 sin 2 2 I Im 2
so that
Assume that the periodic waveform of Fig. 1-22 is a current (rather than a voltage). (a) the average value of the current and (b) the rms value of the current.
Copyright © OnBarcode.com . All rights reserved.