Fig. 5.18 in .NET framework

Generating QR Code in .NET framework Fig. 5.18

Fig. 5.18
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5.6 Refer to Fig. 5.19. A body at O is being acted upon by two forces, one of 150 lb due north and the other of 200 lb due east. Find the magnitude and direction of the resultant.
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In the right triangle OBC, OC 2(OB)2 150/200 (BC)2 2(200)2 (150)2 36 50 . 250 lb, tan / BOC 0.7500, and / BOC
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The magnitude of the resultant force is 250 lb and its direction is N53 10 E.
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CHAPTER 5 Practical Applications
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Fig. 5.19
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5.7 An airplane is moving horizontally at 240 mi/h when a bullet is shot with speed 2750 ft/s at right angles to the path of the airplane. Find the resultant speed and direction of the bullet.
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The speed of the airplane is 240 mi/h 240(5280) ft/s 60(60) 352 ft/s.
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In Fig. 5.20, the vector AB represents the velocity of the airplane, the vector AC represents the initial velocity of the bullet, and the vector AD represents the resultant velocity of the bullet. In the right triangle ACD, AD 2(352)2 352/2750 (2750)2 2770 ft/s. 7 20 or 7.3 .
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tan / CAD
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0.1280, and / CAD
Thus, the bullet travels at 2770 ft/s along a path making an angle of 82 40 or 82.7 with the path of the airplane.
Fig. 5.20
5.8 A river flows due south at 125 ft/min. A motorboat, moving at 475 ft/min in still water, is headed due east across the river. (a) Find the direction in which the boat moves and its speed. (b) In what direction must the boat be headed in order to move due east, and what is its speed in that direction
(a) Refer to Fig. 5.21. In right triangle OAB, tan u OB 125/475 2(475)2 (125)2 491, 14 40 . 0.2632, and u
Thus the boat moves at 491 ft/min in the direction S75 20 E. (b) Refer to Fig. 5.22. In right triangle OAB, sin 125/475 headed N74 40 E and its speed in that direction is OB 2(475)2 (125)2 0.2632 and 458 ft/min 15 20 . Thus the boat must be
Fig. 5.21
Fig. 5.22
CHAPTER 5 Practical Applications
5.9 A telegraph pole is kept vertical by a guy wire which makes an angle of 25 with the pole and which exerts a pull of F 300 lb on the top. Find the horizontal and vertical components Fh and Fv of the pull F. See Fig. 5.23.
Fh Fv 300 sin 25 300 cos 25 300(0.4226) 300(0.9063) 127 lb 272 lb
Fig. 15.23
5.10 A man pulls a rope attached to a sled with a force of 100 lb. The rope makes an angle of 27 with the ground. (a) Find the effective pull tending to move the sled along the ground and the effective pull tending to lift the sled vertically. (b) Find the force which the man must exert so that the effective force tending to move the sled along the ground is 100 lb.
(a) In Figs. 5.24 and 5.25, the 100-lb pull in the rope is resolved into horizontal and vertical components, Fh and Fv, respectively. Then Fh is the force tending to move the sled along the ground, and Fv is the force tending to lift the sled. Fh Fv 100 cos 27 100 sin 27 100(0.8910) 100(0.4540) 89 lb 45 lb 100 lb. Then
(b) In Fig. 5.26, the horizontal component of the required force F is Fh F 100/cos 27 100/0.8910 112 lb
Fig. 5.24
Fig. 5.25
Fig. 5.26
5.11 A block weighing W 500 lb rests on a ramp inclined 29 with the horizontal. (a) Find the force tending to move the block down the ramp and the force of the block on the ramp. (b) What minimum force must be applied to keep the block from sliding down the ramp Neglect friction.
(a) Refer to Fig. 5.27. Resolve the weight W of the block into components F1 and F2, respectively parallel and perpendicular to the ramp. F1 is the force tending to move the block down the ramp and F2 is the force of the block on the ramp. F1 F2 (b) 242 lb up the ramp W sin 29 W cos 29 500(0.4848) 500(0.8746) 242 lb 437 lb
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