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qr code vb.net free HighPass Constantk Filter in VS .NET
HighPass Constantk Filter Code 128 Code Set C Reader In Visual Studio .NET Using Barcode Control SDK for Visual Studio .NET Control to generate, create, read, scan barcode image in VS .NET applications. Code 128 Creation In VS .NET Using Barcode generation for .NET Control to generate, create Code128 image in Visual Studio .NET applications. " " Here again we study a form of symmetrical T network in which Z1 and Z2 are pure reactances of opposite sign where, using the terminology of Fig. 202, " " Z1 jXC j=!C and Z2 jXL j!L " and where the network is terminated in a pure resistance of ZL RL ohms, as shown in Fig. 210. Code128 Decoder In .NET Framework Using Barcode reader for .NET Control to read, scan read, scan image in Visual Studio .NET applications. Bar Code Creation In .NET Framework Using Barcode maker for .NET framework Control to generate, create bar code image in VS .NET applications. Fig. 210
Bar Code Reader In .NET Using Barcode decoder for .NET framework Control to read, scan read, scan image in .NET applications. Draw Code 128A In Visual C#.NET Using Barcode encoder for .NET framework Control to generate, create Code 128 Code Set B image in .NET framework applications. Note that at very LOW frequencies the reactances of the series capacitors are very " HIGH and the reactance of the shunt inductor is very LOW, so that V2 is very LOW at such frequencies. On the other hand, at very HIGH frequencies the reactances of the series Making Code 128 Code Set A In .NET Using Barcode maker for ASP.NET Control to generate, create Code 128 Code Set A image in ASP.NET applications. Draw Code 128B In Visual Basic .NET Using Barcode creation for VS .NET Control to generate, create Code128 image in Visual Studio .NET applications. CHAPTER 9 Impedance Transformation
UPC  13 Creation In Visual Studio .NET Using Barcode creator for .NET framework Control to generate, create EAN 13 image in .NET applications. Paint Code 128 In .NET Using Barcode generation for VS .NET Control to generate, create Code128 image in .NET applications. " capacitors are very LOW and the reactance of the shunt inductor is very HIGH, so that V2 "1 at such frequencies. Thus (in just a general way) we see that Fig. is nearly EQUAL to V 210 constitutes a highpass type of lter. But now let us get down to speci c details. To do this, we begin by noting that the two equations following Fig. 208 apply equally well to Fig. 210; thus, if you will now substitute into the second equation following Fig. 208 the values " Z1 j=!C and " Z2 j!L " and ZL RL and then, after doing this, multiply the numerator and denominator by j=!LRL , you should nd that " V2 V1 1 1 j !LRL 2!2 LC 1 1 L 4!2 C 2 C 360 GS1 RSS Maker In .NET Framework Using Barcode generator for VS .NET Control to generate, create DataBar image in .NET framework applications. British Royal Mail 4State Customer Code Maker In VS .NET Using Barcode generator for .NET Control to generate, create Royal Mail Barcode image in .NET framework applications. Now let s pause and try to decide upon a reasonable value for RL . To do this, we note that at very HIGH frequencies Fig. 210 would, for all practical purposes, become as shown in Fig. 211. Barcode Encoder In None Using Barcode creation for Microsoft Word Control to generate, create barcode image in Office Word applications. EAN 13 Creator In Java Using Barcode creation for Android Control to generate, create GTIN  13 image in Android applications. Fig. 211
Create GS1 128 In Visual C#.NET Using Barcode drawer for VS .NET Control to generate, create UCC128 image in VS .NET applications. USS Code 39 Creator In None Using Barcode printer for Online Control to generate, create Code 39 Extended image in Online applications. Thus, for very HIGH values of ! the generator would see a pure resistance of RL ohms, " " in which V2 =V1 1, with zero phase shift between V2 and V1 . This would be the desired condition here, because Fig. 210 is to be a HIGHPASS lter. " " With this in mind, and upon setting Z1 j=!C and Z2 j!L in eq. (340), we have that the characteristic impedance of the Tnetwork of Fig. 210 is equal to r L 1 " 2 2 Z0 C 4! C in which, as you ll note, the value of the term 1=4!2 C 2 decreases rapidly in value as ! " increases; thus, at the p preferred HIGH frequencies the value of Z0 becomes, for practical purposes, equal to L=C ohms. It thus makes sense to let r L " 361 Z0 RL C because this will cause Fig. 210 to become equal to the desired condition of Fig. 211 at high frequencies. Next, let us try to express eq. (360) in terms of a dimensionless ratio !=!0 , as we did for the case of the lowpass lter (eq. (353)). To do this, let us begin by noting that the imaginary term in the denominator of eq. (360) can be written as j 1 j 1 1 L 1 !LCRL 4!2 C !C RL 4!2 LC j 1 p 1 362 ! LC 4!2 LC USS Code 128 Printer In Java Using Barcode creation for Eclipse BIRT Control to generate, create Code 128 Code Set C image in Eclipse BIRT applications. Encoding ECC200 In None Using Barcode printer for Font Control to generate, create Data Matrix image in Font applications. CHAPTER 9 Impedance Transformation
Create Barcode In Java Using Barcode creation for Android Control to generate, create bar code image in Android applications. Making Code39 In Java Using Barcode creator for Java Control to generate, create Code 3/9 image in Java applications. because, by eq. (361), j 1 j !C RL ! " V2 V1 1 r C j p LC 2 ! LC 1
Thus, upon substituting the j term (eq. (362)) into eq. (360), we have the desired form 1 1 j p 2!2 LC ! LC 1 1 4!2 LC 363 The above form is especially useful because it can readily be expressed in terms of the ratio of any frequency ! to a xed reference frequency !0 . This can be done by de ning that the reference frequency be equal to 1 !0 p 2 LC 364 p Thus, LC 1=2!0 and LC 1=4!2 , and upon making these substitutions into eq. 0 (363), then making the substitution h !=!0 365 (that is, !0 =! 1=h , and then multiplying the numerator and denominator by h , you should nd that eq. (363) becomes " h3 V2 V1 h h2 2 j2 1 h2 366 " If, now, we wish to investigate only the manner in which the magnitude of V2 =V1 varies with frequency, then eq. (366) becomes " V2 h3 h3 q p V 4 h6 4h2 1 h2 h2 2 2 4 1 h2 2 p or, since 1= X 1=X 1=2 X 1=2 , we can write the above in the form " V2 h3 4 h6 4h2 1=2 V 1 or, in decibels (see notes 19 and 22 in the Appendix and eqs. (319), (320), and (321)), the above equation becomes dB 60 log h 10 log 4 h6 4h2 367 Using your calculator, you can verify that the following table of values is correct for eq. (367), in which we ve rounded o the dB values to two decimal places. h 0.2 0.4 0.6 0.8 1.0 1.1 dB 47.78 29.15 17.47 8.13 0.00 2.79 h 1.2 1.3 1.4 1.5 1.6 1.7 dB 3.87 3.68 3.10 2.51 2.02 1.63 h 1.8 1.9 2.0 2.5 3.0 4.0 dB 1.33 1.09 0.90 0.39 0.20 0.06

