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qr code vb.net source V1 =R V1 =V2 2 2 V2 =R in VS .NET
Appendix Code 128 Code Set B Reader In VS .NET Using Barcode Control SDK for VS .NET Control to generate, create, read, scan barcode image in VS .NET applications. Code 128B Creator In VS .NET Using Barcode printer for .NET framework Control to generate, create Code 128 Code Set C image in .NET applications. The truth of eq. 9A can be established as follows. let meaning that raise both sides to power n by definition hence; since y log x log x y x 10y xn 10yn log xn yn log xn n log x Code128 Scanner In .NET Using Barcode decoder for Visual Studio .NET Control to read, scan read, scan image in .NET applications. Generate Barcode In .NET Framework Using Barcode generation for VS .NET Control to generate, create bar code image in VS .NET applications. thus proving eq. (9A). Let us now make use of eq. (9A) as follows. Recall that, in a purely resistive circuit, POWER can be calculated by the equation V 2 =R. Thus, for two voltages, V1 and V2 , applied to a resistance of R ohms, the POWER RATIO is P Bar Code Decoder In Visual Studio .NET Using Barcode recognizer for VS .NET Control to read, scan read, scan image in .NET framework applications. Code128 Encoder In Visual C#.NET Using Barcode drawer for .NET Control to generate, create Code 128 Code Set A image in VS .NET applications. 2 V1 =R V1 =V2 2 2 V2 =R
Code 128 Code Set C Creation In .NET Using Barcode creation for ASP.NET Control to generate, create USS Code 128 image in ASP.NET applications. Code 128A Creation In VB.NET Using Barcode creator for .NET Control to generate, create Code128 image in .NET applications. and thus, substituting this value of P in eq. (315) then making use of eq. (9A), eq. (315) becomes dB 20 log V1 =V2 10A Code 128 Creator In .NET Using Barcode maker for .NET Control to generate, create Code128 image in Visual Studio .NET applications. Encoding EAN 128 In VS .NET Using Barcode generation for .NET framework Control to generate, create GTIN  128 image in .NET framework applications. which, it should be noted, is true only if V1 and V2 are both applied to the same value of resistance of R ohms. Actually, however, in practice eq. (10A) is often applied in cases where the two resistances are not equal; in such a case the results are not really in decibels but in what we could call logarithmic units. GS1 DataBar Stacked Drawer In .NET Using Barcode printer for Visual Studio .NET Control to generate, create GS1 DataBar14 image in Visual Studio .NET applications. USPS PLANET Barcode Printer In .NET Using Barcode creation for Visual Studio .NET Control to generate, create USPS Confirm Service Barcode image in VS .NET applications. Note 20.
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Paint Data Matrix In ObjectiveC Using Barcode creation for iPhone Control to generate, create DataMatrix image in iPhone applications. DataMatrix Maker In .NET Framework Using Barcode creator for Reporting Service Control to generate, create Data Matrix ECC200 image in Reporting Service applications. It s been pointed out that frequency discrimination (frequency distortion) is produced by the presence of AMPLITUDE DISTORTION and TIMEDELAY (PHASE) DISTORTION. First, in regard to amplitude distortion, it s clear that no amplitude distortion can occur if, in passing through a network, the amplitudes of all frequency components are multiplied by a xed constant value k; that is, if all frequency components are treated the same, as far as amplitudes are concerned. Let us, therefore, turn our attention to timedelay distortion, as follows. Since there is energy storage associated with inductance and capacitance, it s understandable that time is required to change the state of energy level in these parameters. Because of this, a time delay exists between the input and output waves of voltage and current in a network. If such time delay is the same for all frequency components, then there is no distortion due to time delay. This is illustrated in Figs. 27A and 28A, in which the INPUT signal, Fig. 27A, consists of fundamental, secondharmonic, and fourthharmonic waves, having amplitudes and positions as shown, the independent variable being time, t. Now let T denote the time delay between input and output waves, and suppose we have the desired condition in which T is the same for all frequency components, which is the condition illustrated in Fig. 28A. Comparison of the two gures makes clear that if there is no amplitude distortion, and if the TIME DELAY is the SAME FOR ALL FREQUENCIES, then the output wave will be delayed, relative to the input wave, by T seconds, but the basic WAVESHAPE of the output wave will be the SAME as that of the input wave. Make Barcode In Java Using Barcode creation for BIRT Control to generate, create bar code image in BIRT reports applications. Bar Code Recognizer In Java Using Barcode decoder for Java Control to read, scan read, scan image in Java applications. Appendix
Bar Code Recognizer In Visual C# Using Barcode decoder for .NET Control to read, scan read, scan image in VS .NET applications. Create EAN13 In None Using Barcode creator for Office Excel Control to generate, create EAN / UCC  13 image in Microsoft Excel applications. Fig. 27A. INPUT wave.
Fig. 28A. OUTPUT wave.
As already noted, timedelay distortion is also called phase distortion. If we choose to talk in terms of phase distortion, the two conditions for distortionless transmission through a network are that (1) there be no amplitude distortion, and (2) a linear ( rst degree) relationship exist between phase shift and order of harmonic in the output wave. The meaning of this statement can be explained as follows. We recall, from note 18, that any nonsinusoidal repetitive waveform can be expressed as the sum of a fundamental sinusoidal wave and its harmonics, in which the amplitudes of the harmonics decrease in a general way as the order of the harmonic increases. With this in mind, let vi denote the instantaneous value of such a voltage waveform applied to the INPUT of a network, and let the Fourier series for vi be of the form vi a1 sin !t a2 sin 2!t an sin n!t 11A where a1 sin !t is the fundamental (lowest frequency) component, a2 sin 2!t is the secondharmonic component, and so on, to any nth harmonic component of amplitude an and frequency n!. Now suppose, in passing through the network, that all the amplitudes are multiplied by the same constant value k (thus no amplitude distortion), and that all the components are delayed by the same amount of T seconds. In such a case, upon setting ka1 b1 ; ka2 b2 , and so on, and upon replacing t with t T),* eq. (11A) becomes the OUTPUT VOLTAGE of the network vo b1 sin !t !T b2 sin 2!t 2!T bn sin n!t n!T 12A Equation (12A) is true for the ideal condition in which all frequency components are delayed the same amount of time, T seconds, in passing through a network. Thus an sin n!t, applied at the INPUT, appears at the OUTPUT as bn sin n!t n bn sin n!t n!T

